Math, asked by bmb5617, 9 months ago

Give value of - (9(64^1/3 + 125^3)^3)^1/4

Answers

Answered by tejasvimaligi
1

Rewrite 64 and 125 as exponents:

\bigg[ 9 \bigg((4^3)^{\frac{1}{3}} + (5^3)^{\frac{1}{3}} \bigg)^3 \bigg]^{\frac{1}{4}}

Evaluate the exponents:

\bigg[ 9 \bigg(4 + 5\bigg)^3 \bigg]^{\frac{1}{4}}

Add 4 and 5:

\bigg[ 9 \bigg( 9 \bigg)^3 \bigg]^{\frac{1}{4}}

Combine the 9s as exponents:

\bigg[ 9^4 \bigg]^{\frac{1}{4}}

Evaluate the exponents:

9

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Answered by khushikumari7674
1

Answer:

[9(64⅓+125⅓) ³]¼

Rewrite 64 and 125 as exponents:

[9(4³) ⅓+(5³) ⅓]¼

Evaluate the exponents:

[9(4+5) ³]¼

Add 4 and 5:

[9(9) ³]¼

Combine the 9s as exponents:

[9⁴]¼

Evaluate the exponents:

9

.

Answer: 9.......

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