give value of n and l for an unpaired electron in Cu 29
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Answered by
60
Copper-Cu- Atomic Number 29
Electronic Configuration : 1s2 2s2 2p6 3s2 3p6 4s1 3d10
So unpaired electron =4S1
The required Quantum numbers are
Principal quantum number =n=4
Azimuthal quantum number=l=0
Electronic Configuration : 1s2 2s2 2p6 3s2 3p6 4s1 3d10
So unpaired electron =4S1
The required Quantum numbers are
Principal quantum number =n=4
Azimuthal quantum number=l=0
Answered by
3
Answer:
n=4 and l=0
Explanation:
cu = 29 atomic number
=3d10 4s1
in 4s1 N=4 and L=0
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