give zeros of the polynomial p(x) =(x-1) (x-2) (x-3) (x-4)
Answers
To find zeroes , P(x) = 0
(x-1)(x-2)(x-3)(x-4) = 0
x-1 = 0 ; x = 1
x-2 = 0 ; x = 2
x-3 = 0 ; x = 3
x-4 = 0 ; x = 4
hence the zeroes are :- 1,2,3,4
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The zeros of the polynomial p(x) = (x-1) (x-2) (x-3) (x-4) are 1 , 2 , 3 , 4
Given :
The polynomial p(x) = (x-1) (x-2) (x-3) (x-4)
To find :
The zeroes of the polynomial
Solution :
Step 1 of 2 :
Write down the given polynomial
The given polynomial is
p(x) = (x-1) (x-2) (x-3) (x-4)
Step 2 of 2 :
Find the zeroes of the polynomial
For zeroes of the polynomial we have
x - 1 = 0 gives x = 1
x - 2 = 0 gives x = 2
x - 3 = 0 gives x = 3
x - 4 = 0 gives x = 4
Hence the required zeroes are 1 , 2 , 3 , 4
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