Given 0.15 moles of P4 molecules. How many phosphorus atoms are present in this ?
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Given no. of moles = 0.15
we know that Avogadro no. =6.022×10^23
now we have to find the atoms or the no. of particles
now we know that
No. of moles = No. of particles/Avogadro number
therefore, No. of particles or atoms= No. of moles× Avogadro No.
no. of particles=0.15×6.022×10^23
=0.9033×10^23=9.033×10^22
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GOODNIGHT
we know that Avogadro no. =6.022×10^23
now we have to find the atoms or the no. of particles
now we know that
No. of moles = No. of particles/Avogadro number
therefore, No. of particles or atoms= No. of moles× Avogadro No.
no. of particles=0.15×6.022×10^23
=0.9033×10^23=9.033×10^22
HOPE THIS ANSWER HELPS AND IF POSSIBLE PLEASE MARK THIS AS THE BRAINLIEST ANSWER
THANK YOU
GOODNIGHT
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