Question

Given
1) a^2 +b^2 =1
2) d^2 -f2=1
3) e^2 -c^2=1
4) ad=1
5) be=1
6)cf=1
7) a=bc


Prove the following


1) (b+e)(b-e)=-(a^2+c^2)

2) (c/1-f ) +(f/1-c) =1+c+f

3) root over (1-b/1+b) =d-f

4) 1+a-b/1+b+c =1-b/1+b

5) b/d+1 + b/d-1 =2c

6) if 3a+5b =5
then find 5a-3b

7) e^6 = c^6+3c^2e^2+1

8) c^3/1+c^2 + f^3/1+f^2 =de-2ab

9) 1+b-a^2/(1-b)a =f

10) (e+c-1)(e-c+1)=2c

11) bd-ac/a+b =d-c

12) (e-d)(1+c+f)=ce-df

Answer 1

Answer:

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