Question

Given 1176 = 2p.3q.7r, find p. q and r. ​

Answer 1

Answer:

The correct answer is -

p= 4, q=1 and r=7

Step-by-step explanation:

By prime factorization of 1176, we get:

1176= 2×2×2×3×7×7.

1176=2×4×3×1×7×7

Comparing this with 1176=2×p×3×q×7×r, we get:

p=4, q=1, r=7.

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