Given 11x+ 3y=27 and 3x-5y=11 then value of x+y = ?
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Answer:
3 (11x+3y=27)
11 (3x-5y=11)
33x+9y=81
33x-55y=121
subtracting the equations
we get
64y=-40
y=-40/64=-5/8
now putting the value of y in equation
11x+3(-5/8)=27
11x -15/8=27
11x=15/8+27
11x=231/8
x=231/8×11=12/8=3/2
x=3/2, y=-5/8
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