Question

Given 13 sin A = 12 find :
(i)sec - tan A.
(ii)1 /cos²- tan² A.​

Answer 1

Answer:

sinA=12/13

cosA= 5/13

tanA=12/5

secA=13/5

sec sq A= 169/25

tan sqA=144/25

1. 13/5-12/5=1/5

2. 169/25-144/25=25/25=1