Question

given 13x-7y=6 and xy=2.find the value of 169x^2+49y^2​

Answer 1

Answer:

$\large\boxed{\star\:\:\:169x^2+49y^2=400\:\:\:\star}$

Step-by-step explanation:

✢ Given:-

• 13x-7y=6
• x × y=2

✢ To Find:-

   Value of 169 x²+49 y².

✢ Formula Applied:-

   (a+b)²=a²+b²+2ab

✢ Solution:-

 13x-7y=6

 Squaring Both Side:-

⇒ (13x-7y)²=(6)²

⇒ (13x)²+(7y)²-2(13x)(7y)=36

⇒ 169x²+49y²-182xy=36

⇒ 169x²+49y²=36+182(2)          [∵ x × y=2]

⇒ 169x²+49y²=36+364

$\implies\boxed{169x^2+49y^2=400}$