Question

Given 14(a^2 + b^2 + c^2 ) = (a + 2b + 3c)^2 , then find the ratio a:b:c.​

Answer 1

Step-by-step explanation:

14(a^2+b^2+c^2) =(a+2b+3c)^2

14a^2+ 14b^2+ 14c^2 = a^2+ 4b^2 + 9c^2

14a^2-a^2 + 14b^2-4b^2+ 14c^2-9c^2= 0

13a^2+ 10b^2 + 5c^2 =0

13 a^2 + 10 b^2 = - 5 c^2 ...........1

13 a^2 = - 5c^2 -10 b^2. .............2

if we keep value of 13 a^2 in 1

- 5 c^2 -10b^2 + 10 b ^2 = - 5 c^2

at the last 1 will be remain

a:b:c: = 1:1:1 hope it helps if I was wrong than sry

Answer 2

Answer:

its 1:2:3

Step-by-step explanation:

Idk what the process is but I definitely know that the first answer is wrong. (a+2b+3c)^2 is not a^2+4b^2+9c^2 there is something called crossterms. Rookie mistake. it's a^2+4ab+6ac+4b^2+12bc+9c^2 #trashatmaths