Question

given 15 cos A=2 then sin a=?,secA=?

Answer 1

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Answer 2

$Hey\:There$‼

We have, 15 cosA = 2

=> cosA = 2 / 15

As we know,
sin²A + cos²A = 1

=> sin²A = 1 – cos²A

=> sin²A = 1 – (2 / 15)

=> sin²A = (15 – 2) / 15

=> sin²A = 13 / 15

=> sinA = √13 / √15

AND

We know,
cosA = 1 / secA

=> secA = 1 / cosA

=> secA = 1 / ( 2/ 15)

=> secA = 15 / 2