Math, asked by saksham673, 8 months ago


Given 15 cot A = 8, find sin A and sec A.​

Answers

Answered by Anonymous
4

here is your answer...

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Answered by rishisingavarpu
3

Answer: sin A = 5/√89 , sec A = √89/8

Step-by-step explanation:

given, 15 cot A = 8

           =>  cot A = 8/15    [ since , cot A = adjacent side/opposite side]

              adjacent side = 8

              opposite side = 15

        (hypotenuse)²  =  (opposite side)² + (adjacent side )²

                                    =  (15)² + (8)²

                                    =  225 + 64

        (hypotenuse)²  =  289

        =>   hypotenuse = 17

   sin A =  opposite side/hypotenuse       sec A =  hypotenuse/adjacent side

             =  15/17                                                       =  17/8              

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