Question

Given 15 cot A = 8, find sin A and sec A..​

Answer 1

Solution of this question is in attached pic .

Answer 2

Answer:

15 cot A = 8

cot A= 8/15

Now,

Tan A = 1/cotA

= 1/8/15 = 15/8

hence, tan A= 15/8

side opposite to angle A = 15/8

side adjacent to angle A

BC/AB = 15/8

Let,

BC = 15x

nd AB = 8x

Finding AC using phthogaros theoram .

( hypotenuse)² = height + ( Bace )²

AC² = AB² +BC²

AC² = ( 8x)² +( 15x)²

AC 2 = 64x² + 225x²

AC = 17x

Now, we need to find sin A nd Sec A

sinA = side opposite to angle A/ hypotenuse

BC/ AC

15x/17x

15/17

For Sen A , finding Cos A 1st cost A= side adjacenenet to anglr A / hypotenuse

AB/ AC

8x/ 17x

8/17

sec A = 1/ CosA

= 1/8/17 = 17 / 8

Explanation:

hopes it help u ✌