Given 15 cot A = 8 , find sin A and Sec A
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Answered by
626
15 cot A =8
cot A= 8/15
cot A = 8/15 = base/height
________________________________________________
Let height be 15x and base be 8x
By Pythagoras Theorem,
(15x)^2 + (8x)^2 = hypotenuse^2
(225 + 64)x^2 = hypotenuse^2
289x^2 = hypotenuse^2
17x = hypotenuse
_______________________________________________
Now,
sin A = height/hypotenuse
Sin A = 15/17
AND
sec A = hypotenuse/base
Sec A = 17/8
i hope this will help you
-by ABHAY
cot A= 8/15
cot A = 8/15 = base/height
________________________________________________
Let height be 15x and base be 8x
By Pythagoras Theorem,
(15x)^2 + (8x)^2 = hypotenuse^2
(225 + 64)x^2 = hypotenuse^2
289x^2 = hypotenuse^2
17x = hypotenuse
_______________________________________________
Now,
sin A = height/hypotenuse
Sin A = 15/17
AND
sec A = hypotenuse/base
Sec A = 17/8
i hope this will help you
-by ABHAY
Answered by
19
Step-by-step explanation:
15 cot a = 8 find sin A and and sec
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