Given 15 cot A=8,find sin A and sec A.
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Answered by
6
15cotA=8
∴cotA=8/15
Let triangle ABC, right anlged at B
cotѳ=adj. side/ oppo.side
∴AB/BC=8/15
∴AB=8 & BC=15
by pythagoras theorm,
AC2=AB2+BC2
AC2=82+152
AC2=64+225
AC2=289
AC=17
∴sin A= 15/17 &
secA=17/8
∴cotA=8/15
Let triangle ABC, right anlged at B
cotѳ=adj. side/ oppo.side
∴AB/BC=8/15
∴AB=8 & BC=15
by pythagoras theorm,
AC2=AB2+BC2
AC2=82+152
AC2=64+225
AC2=289
AC=17
∴sin A= 15/17 &
secA=17/8
angeldharitri:
ty
Answered by
1
15cot A =8
=>15cosA /sinA = 8
15 sinA secA =8
SecA is 8/15sinA
SinA is 15/8cosA
Hope u like it
Plz mark brainliest
=>15cosA /sinA = 8
15 sinA secA =8
SecA is 8/15sinA
SinA is 15/8cosA
Hope u like it
Plz mark brainliest
the answer is sinA=15/17 sec A=17/8
Ya I know
Actually before completing it showed a problem and only half the answer is posted, only the first part and the last
Extremely sorry for disappointing you
it's okk yrr
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