Question

Given 15 cot A=8, find sin A and sec A.​

Answer 1

Answer:

tan A= 15/8

sin A= 15/7

cos A= 8/7

sec A=7/8

Step-by-step explanation:

Answer 2

Step-by-step explanation:

$15 \cot \theta = 8$

$\cot \theta = \frac{8}{15} = \frac{adjacent}{opposite}$

By Pythagoras theorem,

${ H }^{2} = {B}^{2} + {P }^{2}$

${H}^{2} = {8}^{2} + {15}^{2}$

${H}^{2} = 64 + 225$

${H}^{2} = 319$

$H = \sqrt{319}$

$\sin \theta = \frac{opposite}{hypotenuse} = \frac{15}{ \sqrt{319} }$

$\sec \theta = \frac{hypotenuse}{adjacent} = \frac{ \sqrt{319} }{8}$