Question

Given 15 cot A = 8 , find sin A and sec A .​

Answer 1

Answer:

SinA = 15/17

SecA = 17/8

Step-by-step explanation:

$15CotA=8\\\\CotA=\frac{8}{15} =\frac{Base}{Perpendicular}$

$Base(B) = 8\\\\Perpendicular(P)=15$

Applying Pythagoras theorem,

(H)² = (P)² + (B)²

(H)² = (15)² + (8)²

(H)² = (15)² + (8)²

(H)² = 225 + 64

H = √289

H = 17

$Hypotenuse(H) = 17$

Now,

$SinA=\frac{P}{H} =\frac{15}{17}$

$SecA = \frac{H}{B} =\frac{17}{8}$