Question

given 15 cot A = 8,find sin A and sec A

Answer 1

Answer:

sin A = 15/17 And sec A = 17/8

Step-by-step explanation:

We have to given :

15 cot A = 8

then 15 jo hai vo equal to ke side jayegaa divide me,

iske baad,

cot A = 8 / 15

therefore , cot A = b/p so,

b (base) = 8

p (perpendicular) = 15

By Pythagoras theorem , [ h^2 = p^2 + b^2 ]

8^2 + 15^2 = h^2

64 + 225 = h^2

289 = h^2

square root of 289 = 17,

Therefore,

value of Hypotenuse = 17 ,

sin A = p/h = 15/17

Sec A = h/b = 17/8.

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