Question

given 15 cot A =8,find sin A and sec A.

Answer 1

Step-by-step explanation:

here cotA =8/15

now in equation

cot² A=64/225

or, tan² A=225/64

or, cosec² A-1=225/64

or, cosec² A=225+64/64

therefore cosec A=17/8;now sin A=8/17

again,

cosA/sinA=8/15

or,cosA=8/15 *sinA

or,cos A=8/15*8/17

therefore cos A=64/255;sec A=255/64