Given 15 cot A= 8, find sin A and sec A.
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cot A = 8/15
cot A = Base/Perpendicular
base = 8x
Perpendicular = 15x
since, it is a right angled triangle, we'll use Pythagoras theorem to find the hypotenuse of the triangle
( H )² = ( B )² + ( P )²
= ( H )² = ( 8x )² + ( 15x )²
= ( H )² = 64x² + 225x²
= ( H )² = 289x²
= H = 17x
Now, sin A = Perpendicular/Hypotenuse
= 15x/17x = 15/17.
sec A = Hypotenuse/Base
= 17x/8x = 17/8.
so, your final answer:-
sin A = 15/17
sec A = 17/8.
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