Question

given 15 cot A=8, find sin A and sec A

solve these questions in 2minutes​

Answer 1

Answer:

sin A = 15/17

sec A = 17/8

Step-by-step explanation:

15 cot A = 8

cot A = 8/15

tan A = 15/8

if we imagine a right angle triangle ABC , from Pythagoras theorem we know,

AC² = AB² + BC ²

= 8² + 15²

opposite side

as ,tan (x) = ___________

adjacent side

so AB= adjacent side

AC = opposite side

then AC = ✓ 289

= 17

therefore, secA= AC/ AB

= 17/8

sin A = BC/ AC

= 15/17