Question

given 15 cotA=8,find sinA and tan A​

Answer 1

Step-by-step explanation:

HEY MATE ..

Given,

Given,15cotA=8cotA

=> tanA= 8/15 -------(tanA= cot A / 1 )

We know that,

tan θ= adjacent Side /opposite Side

Consider the attached figure, triangle ABC.

From Pythagoras theorem,AC ^2

2 =AB ^2 +BC ^2

AC ^2 =8 ^2 +15 ^2 =64+225=289

=64+225=289AC=17.

cosA= Hypotenuse /adjacent Side

= AC / AB

AB = 17 / 8

secA= cosA / 1

= 1 /8 / 17 17/18

sinA= Hypotenuse /oppositeSide

= AC /BC

BC = 17 /15.

HOPE IT HELPS YOU

HOPE IT HELPS YOU 30 THANKS + FOLLOW =INBOX

Answer 2

Answer:

15cotA=8

cotA=8/15

Cot A= base/perpendicular

base=8

perpendicular=15

hypotenus=?

by PGT

H^2=B^2+P^2

H^2=(8)^2+(15)^2

H^2=64+225

H^2=289

H=√289

H=17

sinA=perpendicular/hypotenus

sinA=15/17

TanA=perpendicular/base

TanA=15/8