Given 15cot 8 A ,
find sinA and secA.
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Answered by
9
It's 15 cot A = 8
then Cot A = 8/15
we know that cot = base / perpendicular
Base = 8
perpendicular=15
therefore
Hypotenuse = 17
Then sin A = perpendicular / hypotenuse
= 15/17
sec A = h/b
= 17/8
Hope this helps
Mark as BRAINLIEST ⭐ ⭐
then Cot A = 8/15
we know that cot = base / perpendicular
Base = 8
perpendicular=15
therefore
Hypotenuse = 17
Then sin A = perpendicular / hypotenuse
= 15/17
sec A = h/b
= 17/8
Hope this helps
Mark as BRAINLIEST ⭐ ⭐
diyasd8:
Sec A is wrong . It is h/ b
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6
Please mark it as the brainliest if found helpful...
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