Question

Given 15Cot A=8,find Sec A ?​

Answer 1

Step-by-step explanation:

15Cot A=8,

Therefore,

Cot A=8/15

By Pythagoras theorem

We can find third side

( Hypo) sq=(S1) sq+(S2) sq

${hypo}^{2} = {8}^{2} + {15}^{2} \\ \: \: \: \: \: \: \: \: \: \: \: = 64 + 225 \\ hypo = 17$

Sec A =

$sec \: a = \frac{hypotenuse}{ \: adjacent}$

$= > \frac{17}{8}$

Answer 2

$\huge\underline\mathfrak\green{Solution}$

15cot A = 8

cot A = 8/15

Now,

Cot = Height / perpendicular

So,

Height = 8

Perpendicular = 15

So,

Hypotenuse² = 15² + 8²

= 225 + 64 = 289

Hypotenuse = 17

So,

Sec A = 17/8

Thank you! ❤