Question

given 15cot A=8 find sin A and sec A​

Answer 1

Given,

15cotA=8

cotA=158​

=> tanA=815​-------(tanA=cotA1​)

We know that,

tanθ=adjacentSideoppositeSide​

Consider the attached figure, triangleABC

From Pythagoras theorem,

AC2=AB2+BC2

AC2=82+152=64+225=289

AC=17

cosA=HypotenuseadjacentSide​=ACAB​=178​

secA=cosA1​=178​1​817​

sinA=HypotenuseoppositeSide​=ACBC​=1715​

solution

Answer 2

15 cot A = 8

cot A = 8/15

cot A = base/perpendicular = 8/15

so, hypotenuse = √(8)²+(15)² = 17

Other Trigonometric values are :

sin A = perpendicular/hypotenuse = 15/17

cos A = base/perpendicular = 8/17

tan A = perpendicular/base = 15/8

cosec A = hypotenuse/perpendicular = 17/15

sec A = hypotenuse/base = 17/8