Question

Given 15Cot A=8, Find Sin A and Sec A

Thanks

Answer 1

i think that answer is not so clear if that is not so clear i am sorry

Answer 2

Step-by-step explanation:

15Cot A=8,

Therefore,

Cot A=8/15

By Pythagoras theorem

We can find third side

( Hypo) sq=(S1) sq+(S2) sq

${hypo}^{2} = {8}^{2} + {15}^{2} \\ \: \: \: \: \: \: \: \: \: \: \: = 64 + 225 \\ hypo = 17$

Sec A =

$sec \: a = \frac{hypotenuse}{ \: adjacent}$

$= > \frac{17}{8}$

Sin A= opposite/hypo

= 15/17