Given 15cotA = 8 then find sin A and sec A
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Heya user☺☺☺
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rahilsaleem10t:
but the answer is wrong
no i am not the answer is sinA =15/17 and secA =17/8
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15 cot A = 8
cot A = 8 / 15
tan A = 15 / 8
tan^2 A = 225 / 64
1 + tan^2 A = sec^2 A = 289 / 64
sec A = 17 / 8 OR -17 / 8
1 + cot^2 A = csc^2 A = 1 / sin^2 A = 289 / 225
sin^2 A = 225 / 289
sin A = 15 / 17 OR -15 / 17
cot A = 8 / 15
tan A = 15 / 8
tan^2 A = 225 / 64
1 + tan^2 A = sec^2 A = 289 / 64
sec A = 17 / 8 OR -17 / 8
1 + cot^2 A = csc^2 A = 1 / sin^2 A = 289 / 225
sin^2 A = 225 / 289
sin A = 15 / 17 OR -15 / 17
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