Question

Given, 2 = 1.414 and /6 - 2.449, find the value of 1÷(√3-√2-1) to 3 places of decimal.
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Answer 1

Given,

Value of √2 =1.414

and , √6 = 2.449

now ,

value of 1 ÷ (√3-√2-1)

1 ÷ (1.714- 1.414-1)

1÷ -0.7

-10 ÷ 7

-1.428

#BAL

Answer 2

Given - $\sqrt{2} = 1.414$ and $\sqrt{6} = 2.449$

First we find the value of $\sqrt{3}$

$\sqrt{6} = 2.449$

$\sqrt{2}$ x $\sqrt{3}$ = 2.449

1.414 x $\sqrt{3}$ = 2.449

$\sqrt{3}$ = $\frac{2.449}{1.414}$

$\sqrt{3}$ = 1.731

Putting all the values in the expression

$\frac{1}{\sqrt{3}-\sqrt{2}-1 }$

= $\frac{1}{1.731 - 1.414 - 1}$

= $\frac{1}{-0.683}$

= -1.4641

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