Question

Given, √2 = 1.414 and√ 6 = 2.449, find the
value of1/√3-√2-1 correct
to 3 places of decimal
​

Answer 1

$\sqrt{2} = 1.414 \\ \sqrt{6} = 2.449 \\ \\ \\ \frac{1}{ \sqrt{3} } - \sqrt{2} - 1 \\ \frac{1 - \sqrt{6} - \sqrt{3} }{ \sqrt{3} } \\ = > \frac{1 - 2.449 - 1.732}{1.732} \\ = > \frac{1 - 4.181}{1.732} \\ = > - \frac{3.181}{1.732} \\ = > - 1.836$

I hope that helps you