Question

Given √2=1.4142 and
√6=2.4495 . Find the value of 1
/(√3-√2-1) correct to 3 places
of decimal *​

Answer 1

Answer:

-1.465 is your answer for this question

Answer 2

Step-by-step explanation:

First we find the value of \sqrt{3}

3

\sqrt{6}=2.449

6

=2.449

\sqrt{2}\times\sqrt{3}=2.449

2

×

3

=2.449

1.414\times\sqrt{3}=2.4491.414×

3

=2.449

\sqrt{3}=\frac{2.449}{1.414}

3

=

1.414

2.449

\sqrt{3}=1.731

3

=1.731

Now, put all the values in the expression

\frac{1}{\sqrt{3}-\sqrt{2}-1}

3

−

2

−1

1

=\frac{1}{1.731-1.414-1}=

1.731−1.414−1

1

=\frac{1}{-0.683}=

−0.683

1

=-1.4641=−1.4641

Up to 3 decimal place = -1.464