Question

Given 2 log10 x + 1 = log10 250, find x​

Answer 1

Answer:

Step-by-step explanation:

log10 x^2 -log10 250=-1

log10(x^2/250)=-1

(x^2)/250=0.1

X^2=25

X=5

Answer 2

Answer:

5

Step-by-step explanation:

$2 log(x) + 1 = log(250)$

Now, we can write

$log(10) = 1$

So, the question becomes

$2 log(x) = log( {x}^{2} ) \\ = > log( {x}^{2} ) + log(10) = log(250) \\ = > log(10 {x}^{2} ) = log(250) \\ = > 10 {x}^{2} = 250 \\ = > {x}^{2} = 25 \\ = > x = 5 \: ans$