Question

Given :- 2 Triangles ∆ABC and ∆DEF such that
angle A = angle D
angle B = angle E
angle C = angle F

To Prove : ∆ ABC ~ ∆DEF

[ Hint :- Draw P and Q on DE & DF such that DP = AB and DQ = AC respectively and join PQ ]​

Answer 1

Answer:

In △ABC and △DEF,

∠A=∠D ....(Given)

AB=FD ....(Given)

and △ABC≅△DFE ....(SAS rule)

It is possible, if corresponding sides are equal, AC=ED

Answer 2

Answer:

by (A.A.A similar criteria) ∆ABCsimilar to ∆DEF

it's too easy question..