Given 2205 = 3ᵃ x 5ᵇ x 7ᶜ , find the numerical value of a.
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2205 = 3^a * 5^b * 7^c
2205 = 3*3*5*7*7
Therefore 3^a * 5^b * 7^c = 3^2 * 5^1 * 7^2
By comparison a = 2
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2205 = 3*3*5*7*7
Therefore 3^a * 5^b * 7^c = 3^2 * 5^1 * 7^2
By comparison a = 2
Hope it helps you
Mark as brainliest and follow me
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