Question

Given 2205 = 3ᵃ x 5ᵇ x 7ᶜ , find the numerical value of a. ​

Answer 1

2205 = 3^a * 5^b * 7^c


2205 = 3*3*5*7*7


Therefore 3^a * 5^b * 7^c = 3^2 * 5^1 * 7^2
By comparison a = 2

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