Question

Given 29 sinA = 20, find 2+cot²A.

Answer 1

SinA=20/29

AB^2+BC^2=AC^3
=>400+BC^2=841
=>BC^2=441
=>BC=21

2+cot^2A
=2+(21^2/20^2)
=2+(441/400)
=1241/400
=3.16

Answer 2

$\sin(a) = \frac{20}{29} \\ \csc(a) = \frac{29}{20} \\ { \cot( a ) }^{2} = { \csc(a) }^{2} - 1 \\ = {( \frac{29}{20}) }^{2} - 1\\ = \frac{841}{400} - 1 \\ = \frac{441}{400} \\ 2 + { \cot(a) }^{2} = 2 + \frac{441}{400} = \frac{1241}{400}$