Given 2x+3y =K when solution is -3/2 and 1/2 find K
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Case 1
x=(-3) y=2
substitute the values and find
2x + 3y
= 2(-3) + 3(2)
= -6+6
= 0
Case 2
x=1 y=2
substitute the values and find
2x + 3y
= 2(1) + 3(2)
= 2 + 6
= 8
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