Question

Given 3 (log 5 - log 3) - (log 5 - 2 log 6) = 2 - log n, find n.​

Answer 1

Answer:

Answer is n =  $e^2$ / 33.33

Step-by-step explanation:

Given

        3 (log 5 - log 3) - (log 5 - 2 log 6) = 2 - log n

     ⇒3 log(5/3) - (log 5 - log$6^2$) = 2 - log n

     ⇒ log $(5/3)^3$ - log (5/36) = 2 - log n

     ⇒ log { $(5/3)^3$ /  (5/36)} = 2 - log n

     ⇒ log {(5×5×5×36)/(3×3×3×5)} = 2 - log n

     ⇒ log 33.33 + log n = 2

     ⇒ log (n33.33) = 2

     ⇒ n33.33 = $e^2$

     ⇒ n =  $e^2$ / 33.33