Given 3 tanA tanB=1 show that 2cos(A+B)= cos(A-B)
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so, tan a tanb =1/3given 3 tan a tanb=1
now ;sina sinb /cos a cos b=1/3change them in sin and cosapply componendo and dividendo ruleuse the forlmulae for cos(a+b) and cos (a-b). you will get your answer.
now ;sina sinb /cos a cos b=1/3change them in sin and cosapply componendo and dividendo ruleuse the forlmulae for cos(a+b) and cos (a-b). you will get your answer.
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