Given 32 = 2*, and 243 = 3”, then the value of (32 x 243)x-y
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Given that,
3^(x - y) = 27 ….(i)
3^(x + y) = 243 ….(ii)
To solve this equations, you first need to know a law-
If a^x = a^y, then x = y.
From equation (i), we get -
3^(x - y) = 27
=> 3^(x - y) = 3^3 [From the law described above]
=> x - y = 3
=> y = x - 3 … (iii)
Now, from equation (ii), we get -
3^(x + y) = 243
=> 3^(x + y) = 243
=> 3^(x + y) = 3^5
=> x + y = 5 [From the law described above]
=> x + (x - 3) = 5 [Because, from equation (iii) y = x - 3 ]
=> x + x - 3 = 5
=> 2x - 3 = 5
=> 2x = 5 + 3
=> 2x = 8
=> x = 8/2
=> x = 4
So, x = 4
Thank you.
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