Given (3m + n)2 = 100 and (3m - n)2 = 4
What is the value of mn?
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Answer:
(3m+n)2=100
6m+2n=100
6m+n=100/2
6m+n=50
(3m-n)2=4
6m-2n=4
6m-n=4/2
6m-n=2
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