Question

given 3x^2+x=1,find the value of 6x^3-x^2-3x+2010

Answer 1

Answer:

The value of $6x^3-x^2-3x+2010$ is 2009

Step-by-step explanation:

Given:

$3x^2+x=1$

$\implies\:3x^2+x-1=0$......(1)

Now,

By polynomial division,

$6x^3-x^2-3x+2010=(2x-1)(3x^2+x-1)+2009$

$\implies\:6x^3-x^2-3x+2010=(2x-1)(0)+2009$ (using (1))

$\implies\:6x^3-x^2-3x+2010=0+2009$

$\implies\:6x^3-x^2-3x+2010=2009$

Answer 2

Answer:

Step-by-step explanation:

here you go thank you