Question

Given 4 sin A = 3 cos A find sin A​

Answer 1

4sinA=3cosA

sinA/cosA=3/4

tanA=3/4

Now make a triangle with adjacent and opposite sides as 4 and 3. As the angle made by these 2 is 90°, using Pythagoras theorem, the third side is 5(hypotenuse).

Now sinA=opposite/hypotenuse

=3/5