Question

Given 4 sin A =3, find cos A and tan ​

Answer 1

Answer:

4sin A=3

sinA =3/4

sinA =3/4=p/h

now we know P=3, H=4

applying pythagoras theorem

h²=b²+p²

(4)²=b²+(3)²

16=b²+9

b²=16-9

b²= 7

b=√7

p=3,h=4,b=√7

Step-by-step explanation:

cosA =b/h=√7/4

tanA= p/b= 3/√7