Given:4sin theta =3cos theta. Find value. 1.sin theta 2.cos theta
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4sintheta = 3costheta
=>(sin theta )/(costheta)=3/4
=> tan theta =3/4
therefore perpendicular=3, base = 4 therefore hypotenuse =√(3^2+4^2)=5
therefore
1) sin theta=3/5=3:5
2) cos theta = 4/5=4:5
tan theta=3/4=3:4
cosec theta=5/3=5:3
sec theta =5/4=4:5
cot theta =4/3=3:4
=>(sin theta )/(costheta)=3/4
=> tan theta =3/4
therefore perpendicular=3, base = 4 therefore hypotenuse =√(3^2+4^2)=5
therefore
1) sin theta=3/5=3:5
2) cos theta = 4/5=4:5
tan theta=3/4=3:4
cosec theta=5/3=5:3
sec theta =5/4=4:5
cot theta =4/3=3:4
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