Given 5 cos A -12 sin A = 0, find the value of
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5 cos A = 12 sin A
.'. Your question says sin A + cos A = sinA + 12/5 sinA = 17sinA / 5
Also, 2cosA - sinA = 24/5 sinA - sinA = 19 sinA/5
Dividing both, we have:- (sin A + cos A)/(2cosA - sinA) = 17 / 19
.'. Your question says sin A + cos A = sinA + 12/5 sinA = 17sinA / 5
Also, 2cosA - sinA = 24/5 sinA - sinA = 19 sinA/5
Dividing both, we have:- (sin A + cos A)/(2cosA - sinA) = 17 / 19
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Hope this helps.
Hope this helps.
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thats right it came in the NTSE exam which held on 5th november
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