Given 5 different green dyes,4 different blue dyes and 3 different red dyes how many combination of dyes can be chosen, taking at least 1 green and at least 1 blue dye
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Green dyes = 5
Blue dyes = 4
Red dyes = 3
No. of ways of choosing at least one green and at least one blue
= (2^(5) - 1) (2^(4) - 1)(2^3)
= 3720
Blue dyes = 4
Red dyes = 3
No. of ways of choosing at least one green and at least one blue
= (2^(5) - 1) (2^(4) - 1)(2^3)
= 3720
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