Question

Given 5sinA=3 find secA-tanA

Answer 1

Answer:

5sin A= 3

sinA =opp/hyp

=3/5

Let BC be 3k AC be 5k (k is the positive real no.)

By applying Pythagoras theorem

AC2 = AB2 +BC2

(5)2 = (AB)2+ (3)2

25 = (AB)2+ 9

25- 9= AB2

16 = AB2

4 = AB

Sec A =5/3

tan A = 3/4

secA -tanA

5/3 - 3/4

LCM of 3 & 4 =12

5 - 3/12

2 /12

6