Math, asked by aparnaachuthath7, 9 months ago

Given 609x + 957y = A where A is the hcf of 609 and 957

Answers

Answered by prapanna3

Answer:

x=3 and y= 2

Step-by-step explanation:

k=609x+957y957=609×1+348609−348×1+87261=87×3+0now87=348−261×187=348−(609−348×1)×187=348−(609−(957−609×1)×1)87=−957−609×1(609−957+609)87=957×2+609×3x=3y=2

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