Question

Given 9cos A = 8, find tanA and cosec A.

Answer 1

Answer:

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Step-by-step explanation:

tanA=5/9

cosecA=8/5

Answer 2

Step-by-step explanation:

9cosA=8

cosA=8/9

sin²A+cos²A=1

sinA=√1–cos²A

sinA=√1–(8/9)²

sinA=√1–64/81

sinA=√81–64/81

sinA=√17/9

cosecA=1/sinA

cosecA=9/√17

tanA=sinA/cosA

tanA=√17/9/8/9

tanA=9√17/72