Question

Given: A(0,0), B(0,3), C(4,0), D(0,6) and E(8,0) prove abc~ade

Answer 1

using distance formula we can got the answer

in tri. ABC

AB = √ ( 0 -0 )2 + ( 3 -0 ) 2

= √ 0 + 9
= √ 9


BC = √ (4-0)2 + (0 - 3 ) 2
= √ ( 4*2 + ( (-3) *2 )
= √ 16 + 9
= √ 25
= 5

AC = √ (4-0) 2 + (0-0 ) 2
= √ 4 *2
= √ 16
= 4

in tri. ADE
AD = √ ( 0-0)2 + (6-0)2
=√ ( 6*2
= 6

DE = √ ( 8-0)2 + ( 0-6) 2
= √ ( 64 + 12 )
= √ 76

EA = √ ( 8-0)2 + (0-0)2
= √ 8 *2
= 64

hence there is no any similar vertices so the triangle ABC is not ~to ADE

hope it help u

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