Question

given A=0.3i+0.4j+Ck, calculate the value of C if A is a unit vector.

Answer 1

For a unit vector, magnitude is 1
$\sqrt{ {0.3}^{2} + {0.4}^{2} + {c}^{2} } = 1 \\ 0.25 + {c}^{2} = 1 \\ {c}^{2} = 0.75 \\ c = \sqrt{0.75} = 0.87$

Answer 2

Answer:

For a unit vector, magnitude is 1

\begin{gathered}\sqrt{ {0.3}^{2} + {0.4}^{2} + {c}^{2} } = 1 \\ 0.25 + {c}^{2} = 1 \\ {c}^{2} = 0.75 \\ c = \sqrt{0.75} = 0.87\end{gathered}0.32+0.42+c2=10.25+c2=1c2=0.75c= root0.75=0.87